Update Postman collection

backend/src/main/resources/db/migration/V16__activate_all_employees.sql

@@ -1,4 +1,3 @@
--- Activate all employees in the users table so they appear in dropdowns
 UPDATE users u
 SET u.active = TRUE
 WHERE u.role IN ('STAFF', 'ADMIN')

backend/src/main/resources/db/migration/V17__normalize_appointment_pets.sql

@@ -1,7 +1,3 @@
--- V17: Normalize legacy appointmentPet data into customer_pet and appointment_customer_pet
-
--- Step 1: Ensure a customer_pet exists for every pet linked in appointmentPet
--- Note: pet species and breed might be null in pet table, but we copy them over if present
 INSERT INTO customer_pet (customer_id, pet_name, species, breed)
 SELECT DISTINCT a.customerId, p.petName, p.petSpecies, p.petBreed
 FROM appointmentPet ap
@@ -12,7 +8,6 @@ WHERE NOT EXISTS (
     WHERE cp.customer_id = a.customerId AND cp.pet_name = p.petName
 );
 
--- Step 2: Link the appointment to the customer_pet
 INSERT INTO appointment_customer_pet (appointment_id, customer_pet_id)
 SELECT ap.appointmentId, cp.customer_pet_id
 FROM appointmentPet ap
@@ -24,5 +19,4 @@ WHERE NOT EXISTS (
     WHERE acp.appointment_id = ap.appointmentId AND acp.customer_pet_id = cp.customer_pet_id
 );
 
--- Step 3: Remove the old legacy relationships so it strictly uses the new ones
 DELETE FROM appointmentPet;

backend/src/main/resources/db/migration/V18__past_appointments_missed.sql

@@ -1,7 +1,3 @@
--- V18: Normalize past appointments and resolve initial employee double-bookings
-
--- Part 1: Normalize past appointments.
--- Any appointment that is still 'Booked' but the date/time has passed should be marked as 'Missed'.
 UPDATE appointment
 SET appointmentStatus = 'Missed'
 WHERE LOWER(appointmentStatus) = 'booked'
@@ -10,8 +6,6 @@ WHERE LOWER(appointmentStatus) = 'booked'
     OR (appointmentDate = CURRENT_DATE AND appointmentTime < CURRENT_TIME)
   );
 
--- Part 2: Resolve potential double-bookings caused by V15's simple backfill.
--- MySQL Error 1093 workaround: wrap same-table subqueries in derived tables.
 UPDATE appointment a1
 JOIN (
     SELECT a3.appointmentId